5/(2x^2+5x-9)

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Solution for 5/(2x^2+5x-9) equation: 


D( x )

2*x^2+5*x-9 = 0

2*x^2+5*x-9 = 0

2*x^2+5*x-9 = 0

2*x^2+5*x-9 = 0

DELTA = 5^2-(-9*2*4)

DELTA = 97

DELTA > 0

x = (97^(1/2)-5)/(2*2) or x = (-97^(1/2)-5)/(2*2)

x = (97^(1/2)-5)/4 or x = (-(97^(1/2)+5))/4

x in (-oo:(-(97^(1/2)+5))/4) U ((-(97^(1/2)+5))/4:(97^(1/2)-5)/4) U ((97^(1/2)-5)/4:+oo)

5/(2*x^2+5*x-9) = 0

2*x^2+5*x-9 = 0

2*x^2+5*x-9 = 0

DELTA = 5^2-(-9*2*4)

DELTA = 97

DELTA > 0

x = (97^(1/2)-5)/(2*2) or x = (-97^(1/2)-5)/(2*2)

x = (97^(1/2)-5)/4 or x = (-(97^(1/2)+5))/4

(x+(97^(1/2)+5)/4)*(x-((97^(1/2)-5)/4)) = 0

5/((x+(97^(1/2)+5)/4)*(x-((97^(1/2)-5)/4))) = 0

x belongs to the empty set

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